Complete Dice Roller

it.mephit.completediceroller

View detailed information for Complete Dice Roller — ratings, download counts, screenshots, pricing and developer details. See integrated SDKs and related technical data.

Total installs
45(45)
Rating
0.0
Released
September 23, 2018
Last updated
September 23, 2018
Category
Tools
Developer
Jure di Mephit
Developer details
Name
Jure di Mephit
E-mail
www.mephit.it@gmail.com
Website
unknown
Country
unknown
Address
unknown
Android SDKs
  • No items.
Complete Dice Roller Header - AppWisp.com

Screenshots

Complete Dice Roller Screenshot 1 - AppWisp.com
Complete Dice Roller Screenshot 2 - AppWisp.com

Description

You can create flexible and powerful formulas, so you can use it with any rpg or board game.

This app uses a custom extended Dice Notation (https://en.wikipedia.org/wiki/Dice_notation). See the in app documentation.

You can discuss and contribute here: https://github.com/giorgiobeggiora/complete-dice-roller

Examples:

- Pathfinder ™ (skill check) = 1d20 + 6 = roll 1d20 then add 6 to the result
- Dungeons & Dragons ™ 3.5 (pc creation) = 4d6-L = drop the lowest says then sum the others
- Dungeons & Dragons ™ 5 (advantage) = 2d20 + H + 2 = keep the highest says then add 2 to the result
- Dungeons & Dragons ™ 5 (disadvantage) = 2d20 + L + 2 = keep the lower says then add 2 to the result
- Legend of the Five Rings ™ = 4k3 = 4d10 + H3 = roll 4d6 then sum the 3 highest dices
- Legend of the Five Rings ™ = 4k3-R + R = 4d10-R1 + R10 + H3 = roll 4d6 then drop and reroll dices with result 1 (the default value when dropping), then keep and reroll dices with result 10 (the default value when keeping), then then sum the 3 highest dices
- Nameless Land ™ = 1d100 = roll 1d100
- Arkham Horror ™ = 2d6 + S5 = count dices greater than or equal to 5 (the result will be 0, 1 or 2)
- Vampire, the Masquerade ™ = 10d10 + S = count dices greater than or equal to 8 (the default value)
- Fudge ™ = 1dF = the result will be -1, 0 or 1
Other = (1d3 + 3d6) + H + S = roll 1d3 and 3d6 and keep only the highest says then count the successes = 0